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Limit of Floor Integral over ln n

1925SpecialistCalculusSequences & Series

Olimpiada Republicană la Matematică

Let $I_{n} = \int_{1}^{n} \frac{[x]}{x^{2}+1} dx$, $n \in \mathbb{N}$, $n \geq 2$. Compute: $\lim_{n \rightarrow \infty} \frac{I_{n}}{\ln n}$.
0 students attempted0% solvedRating 1925

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